The number of ways that N=20 dimes can be distributed among M=10 people is
N!/(n1! n2! ... nM!)
Since there are M people, there are M ways of allocating one dime. There are MxM=M2 ways of allocating 2 dimes. And there are MN ways of allocating N dimes to M people. The probability of having a particular random allocation of dimes is
probability(n1 ... nM) = (1/MN) N!/(n1! n2! ... nM!)
probability(n1=2 ... n10=2) = (1/1020) 20!/2!10 = 2.37 x 10-5
probability(n1=20) = (1/1020) 20!/20! = 1 x 10-20
It turns out that when the number of dimes and the number of people are large, the probability of finding an individual with a certain number of dimes is well approximated by an exponential distribution. The probability of having a little is exponentially larger than the probability of having a lot.
There are many circumstances where a fixed resource is randomly distributed among a large number of things.
For that reason, the exponential distribution arises in many circumstances.
In economics, if we have a fixed amount of money distributed randomly among a fixed number of people, we can expect an exponential distribution of wealth. Many people will be poor and a few will be wealthy. In the case of atoms and molecules, the situation is similar. A fixed amount of energy randomly distributed among a large number of molecules will lead to an exponential distribution of energetic wealth. Many molecules will have relatively little energy and only a few will be highly energetic!
Random allocation of coins and the exponential distribution
Suppose we have a fixed amount of money that we want to randomly allocate among some number of people. For example, let's say we have 20 dimes and 10 people to give them to. What is the most probable way to allocate the dimes at random?