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euv_date/
euv_datesubseconds.pro
topeuv_datesubseconds
time conversion
result = euv_datesubseconds(euvdate, seconds)
subtract some number of seconds from an euv_date
Return value
a new euv_date minus seconds seconds
Parameters
- euvdate in required
starting euv_date
- seconds in required
seconds to subtract
Examples
IDL> print, euv_datesubseconds('200100110', 20)
2001001095940
IDL> print, euv_datesubseconds(['200100110', '200100110'], 20)
2001001095940 2001001095940
IDL> print, euv_datesubseconds(['200100110', '200100110'], [20, 40])
2001001095940 2001001095920
Author information
- History:
Fri Feb 9 19:19:44 2007, Brian Larsen written and tested
Statistics
| Lines: | 14 |
| McCabe complexity: |
File attributes
| Modifcation date: | Thu Dec 4 15:17:50 2008 |
| Lines: | 50 |